Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - Test: Chapter 3: 12

Answer

Refer to the graph below.
1514965203

Work Step by Step

Solve for $y$. $2x-y=3 \\2x-y-2x=3-2x \\-y=3-2x \\-y=-2x+3 \\-1(-y)=-1(-2x+3) \\y=2x-3$ This means that the given equation is equivalent to, and has the same graph as, $y=2x-3$. RECALL: The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept. Thus, the equation $y=2x-3$ has a slope of $2$ and a y-intercept of $(0, -3)$. To graph the given equation, perform the following steps: (1) Plot the y-intercept $(0, -3)$. (2) Use the slope to plot a second point. From $(0, -3)$, move 2 units up (the rise) and 1 unit to the right (the run) to reach $(1, -1)$. Plot $(1, -1)$. (3) Connect the two points using a line to complete the graph. (Refer to the graph in the answer part above.)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.