## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$y-9=−\dfrac{1}{3}(x+2)$
RECALL: The point-slope form of a line's equation is $y−y_1=m(x−x_1)$ where m=slope and $(x_1, y_1)$ is a point on the line. The given line has a slope of $−\dfrac{1}{3}$ (so m=$−\frac{1}{3}$) and contains the point $(−2, 9)$ (so $x_1=−2$, $y_1=9$). Thus, the equation of the line in point-slope form is: $y−9=−\dfrac{1}{3}(x−(-2)) \\y-9=−\dfrac{1}{3}(x+2)$