## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\text{slope}=\dfrac{7}{3}$
RECALL: The slope is equal to rise (increase in vertical height) over run (the horizontal distance). Rise = $y_2-y_1$ Run = $x_2-x_1$ The line contains the points $(-1, -2)$ and $(2, 5)$. Thus, Rise = $5-(-2) = 5+2=7$ Run = $2-(-1) = 2+1=3$ Therefore, the slope of the line is: $=\dfrac{rise}{run} = \dfrac{7}{3}$