## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

x-intercept: $(16, 0)$ y-intercept: $(0, -10)$
Find the x-intercept by setting $y=0$ then solving for $x$: $5x-8y=80 \\5x-8(0)=80 \\5x=80 \\\frac{5x}{5}=\frac{80}{5} \\x=16$ Thus, the x-intercept is $(16, 0)$. Find the y-intercept by setting $x=0$ then solving for $y$: $5x-8y=80 \\5(0)-8y=80 \\-8y=80 \\\frac{-8x}{-8}=\frac{80}{-8} \\y=-10$ Thus, the y-intercept is $(0, -10)$.