Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.6 Slope-Intercept Form - 3.6 Exercise Set - Page 210: 77


The graphs are not perpendicular.

Work Step by Step

RECALL: (1) In the slope-intercept form of a line's equation $y=mx+b$, $m$=slope and $b$ is the y-coordinate of the y-intercept. (2) Perpendicular lines have slopes whose product is $-1$ (or negative reciprocals of each other). Write both equations in slope-intercept form to obtain: First Equation: $y=3x+1$ Second Equation: $6x+2y=5 \\6x+2y-6x=5-6x \\2y=5-6x \\2y=-6x+5 \\\frac{2y}{2}=\frac{-6x+5}{2} \\y=-3x+\frac{5}{2}$ Note that equations have the slopes $3$ and $-3$. Since $3 \cdot (-3) \ne -1$, then the graphs of the two equations are NOT perpendicular lines.
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