Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.6 Slope-Intercept Form - 3.6 Exercise Set: 51

Answer

$\color{blue}{y=0.6x+16}$

Work Step by Step

RECALL: (1) The slope-intercept form of a line's equation is $y=mx+b$ where $m$=slope and $(0, b)$ is the line's y-intercept. (2) The slope is the rise (change in $y$) over run (change in $x$). The given graph has a y-intercept of $(0, 16)$. This means $b=16$. Note that from $(0, 16)$ to the other point on the line $(10, 22)$: rise =$22-16=6$ run = $10-0=10$ Thus, the slope of the line is $\dfrac{rise}{run} = \dfrac{6}{10} = 0.6$. Therefore, the equation of the line in slope-intercept form is $\color{blue}{y=0.6x+16}$.
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