## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\text{Set Builder Notation: } \left\{ x|x\gt-\dfrac{9}{11} \right\} \\\text{Interval Notation: } \left( -\dfrac{9}{11},\infty \right)$
$\bf{\text{Solution Outline:}}$ Use the properties of inequality to solve the given inequality, $4-8x\lt13+3x .$ Write the answer in both set-builder notation and interval notation. $\bf{\text{Solution Details:}}$ Using the properties of inequality, the inequality above is equivalent to \begin{array}{l}\require{cancel} 4-8x\lt13+3x \\\\ -8x-3x\lt13-4 \\\\ -11x\lt9 .\end{array} Dividing both sides by a negative number (and consequently reversing the inequality symbol), the inequality above is equivalent to \begin{array}{l}\require{cancel} -11x\lt9 \\\\ x\gt\dfrac{9}{-11} \\\\ x\gt-\dfrac{9}{11} .\end{array} Hence, the solution set is \begin{array}{l}\require{cancel} \text{Set Builder Notation: } \left\{ x|x\gt-\dfrac{9}{11} \right\} \\\text{Interval Notation: } \left( -\dfrac{9}{11},\infty \right) .\end{array}