## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$70$%
In the given problem, $B=60$ and $P=42.$ Using $P=BR$ or equivalently $R=\dfrac{P}{B},$ then \begin{array}{l}\require{cancel} R=\dfrac{P}{B} \\\\ R=\dfrac{42}{60} \\\\ R=\dfrac{\cancel6(7)}{\cancel6(10)} \\\\ R=\dfrac{7}{10} \\\\ R=0.7 .\end{array} The expression above is equivalent to 70%.