## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 2 - Equations, Inequalities, and Problem Solving - Review Exercises: Chapter 2 - Page 149: 33

#### Answer

$140$

#### Work Step by Step

In the given problem, $P=49$ and $R=0.35.$ Using $P=BR$ or equivalently $B=\dfrac{P}{R},$ then \begin{array}{l}\require{cancel} B=\dfrac{P}{R} \\\\ B=\dfrac{49}{0.35} \\\\ B=\dfrac{\cancel7(7)}{\cancel7(0.05)} \\\\ B=\dfrac{7}{.05} \\\\ B=\dfrac{7}{.05}\cdot\dfrac{100}{100} \\\\ B=\dfrac{700}{5} \\\\ B=140 .\end{array}

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