Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.2 Using the Principles Together - 2.2 Exercise Set - Page 94: 46



Work Step by Step

By combining like terms and using the properties of equality, the solution to the given equation, $ 10-3x=x-2x+40 $, is \begin{array}{l} -3x-x+2x=40-10 \\\\ -2x=30 \\\\ x=\dfrac{30}{-2} \\\\ x=-15 .\end{array} CHECKING: \begin{array}{l} 10-3(-15)=(-15)-2(-15)+40 \\\\ 10+45=-15+30+40 \\\\ 55=55 \text{ (TRUE)} .\end{array} Hence, the solution is $ x=-15 $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.