Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.2 Using the Principles Together - 2.2 Exercise Set: 14

Answer

$z=11$

Work Step by Step

Using the properties of equality, the solution to the given equation, $ 5z+2=57 $, is \begin{array}{l} 5z+2-2=57-2 \\\\ 5z=55 \\\\ \dfrac{5z}{5}=\dfrac{55}{5} \\\\ z=11 .\end{array} Checking: \begin{array}{l} 5(11)+2=57 \\\\ 55+2=57 \\\\ 57=57 \text{ (TRUE)} .\end{array} Hence, the solution is $ z=11 $.
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