Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.2 Using the Principles Together - 2.2 Exercise Set - Page 94: 44



Work Step by Step

By combining like terms and by using the properties of equality, the solution to the given equation, $ 5y+3=2y+15 $, is \begin{array}{l}\require{cancel} 5y-2y=15-3 \\\\ 3y=12 \\\\ y=\dfrac{12}{3} \\\\ y=4 .\end{array} Checking: \begin{array}{l}\require{cancel} 5(4)+3=2(4)+15 \\\\ 20+3=8+15 \\\\ 23=23 \text{ (TRUE)} .\end{array} Hence, $ y=4 $.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.