#### Answer

$\log_{4}{64}+\log_{4}{16}$

#### Work Step by Step

Using $\log_b(xy)=\log_b x +\log_b y,$ the given logarithmic equation, $
\log_{4}{(64\cdot16)}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{4}{64}+\log_{4}{16}
.\end{array}
This can be further reduced to 3+2. Therefore, the expression is equal to 5.