## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\log_{5}{25}+\log_{5}{125}$
Using $\log_b(xy)=\log_b x +\log_b y,$ the given logarithmic equation, $\log_{5}{(25\cdot125)} ,$ is equivalent to \begin{array}{l}\require{cancel} \log_{5}{25}+\log_{5}{125} .\end{array} This can be further reduced to 2+3. Therefore, the expression is equal to 5.