#### Answer

$\log_{5}{25}+\log_{5}{125}$

#### Work Step by Step

Using $\log_b(xy)=\log_b x +\log_b y,$ the given logarithmic equation, $
\log_{5}{(25\cdot125)}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{5}{25}+\log_{5}{125}
.\end{array}
This can be further reduced to 2+3. Therefore, the expression is equal to 5.