#### Answer

$\log_{3}{81}+\log_{3}{27}$

#### Work Step by Step

Using $\log_b(xy)=\log_b x +\log_b y,$ the given logarithmic equation, $
\log_{3}{(81\cdot27)}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{3}{81}+\log_{3}{27}
.\end{array}

Published by
Pearson

ISBN 10:
0-32184-874-8

ISBN 13:
978-0-32184-874-1

$\log_{3}{81}+\log_{3}{27}$

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