Answer
$0.872\sec $
Work Step by Step
Familiarize- According to the provided statement,
$V=48{{T}^{2}}$
Translate- Substitute the value $V=36.5$ in the provided expression.
$\begin{align}
& V=48{{T}^{2}} \\
& 36.5=48{{T}^{2}}
\end{align}$
Carry out- Solve for $T$,
Divide by $\left( 48 \right)$ on both sides,
$\begin{align}
& 36.5=48{{T}^{2}} \\
& \frac{36.5}{48}=\frac{48{{T}^{2}}}{48} \\
& \frac{36.5}{48}={{T}^{2}}
\end{align}$
Taking square roots on both sides,
$\begin{align}
& \frac{36.5}{48}={{T}^{2}} \\
& \sqrt{\frac{36.5}{48}}=\sqrt{{{T}^{2}}} \\
& 0.872=T
\end{align}$
Thus, the hang time is $0.872\sec $.
