Answer
$$ L=\frac{1}{W^2C}$$
Work Step by Step
Solving the equation by isolating the given variable using the rules of Algebra, we find:
$$ W^2=\frac{1}{LC}\\ L=\frac{1}{W^2C}$$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 724: 20
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