Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 723: 9

Answer

$$r=\sqrt{\frac{m_1m_2G}{F}}$$

Work Step by Step

Solving the equation by isolating the given variable using the rules of Algebra, we find: $$ Fr^2=m_1m_2G\\ r=\sqrt{\frac{m_1m_2G}{F}}$$
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