Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.4 Applications Involving Quadratic Equations - 11.4 Exercise Set - Page 723: 5

Answer

$$r=\frac{\sqrt{\pi }\sqrt{A}}{2\pi }$$

Work Step by Step

Solving the equation by isolating the given variable using the rules of Algebra, we find: $$ A=4\pi r^2 \\ r^2=\frac{A}{4\pi }\\ r=\frac{\sqrt{\pi }\sqrt{A}}{2\pi }$$
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