Chapter 10 - Exponents and Radicals - Study Summary - Practice Exercises - Page 692: 21

$3-2i$

Removing the grouping symbol and then combining the real parts and the imaginary parts, the given expression, $ (2-i)-(-1+i) ,$ simplifies to \begin{array}{l}\require{cancel} (2-i)-(-1+i) \\\\= 2-i+1-i \\\\= (2+1)+(-i-i) \\\\= 3-2i .\end{array}