#### Answer

$(x-y)^{4}$

#### Work Step by Step

Using the properties of radicals, the given expression, $
\sqrt[3]{(x-y)^2}\sqrt[3]{(x-y)^{10}}
,$ simplifies to
\begin{array}{l}\require{cancel}
\sqrt[3]{(x-y)^2(x-y)^{10}}
\\\\=
\sqrt[3]{(x-y)^{2+10}}
\\\\=
\sqrt[3]{(x-y)^{12}}
\\\\=
\sqrt[3]{\left[ (x-y)^{4} \right]^3}
\\\\=
(x-y)^{4}
\end{array}
* Note that it is assumed that no radicands were formed by raising negative numbers to even powers.