Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.3 Multiplying Radical Expressions - 10.3 Exercise Set: 3

Answer

FALSE

Work Step by Step

If $x=1$, then $\sqrt{x^2-9}$ is $\sqrt{-8},$ while $x-3$ is $1-3=-2.$ Hence, the given statement is $\text{ FALSE .}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.