## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$s^{2}t^{3}\sqrt[3]{t}$
Using the properties of radicals, the given expression, $\sqrt[3]{s^2t^4}\sqrt[3]{s^4t^6} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{s^2t^4(s^4t^6)} \\\\= \sqrt[3]{s^{2+4}t^{4+6}} \\\\= \sqrt[3]{s^{6}t^{10}} \\\\= \sqrt[3]{s^{6}t^{9}\cdot t} \\\\= \sqrt[3]{(s^{2}t^{3})^3\cdot t} \\\\= s^{2}t^{3}\sqrt[3]{t} \end{array} * Note that it is assumed that no radicands were formed by raising negative numbers to even powers.