Answer
1
Work Step by Step
$\frac{9\times8xy}{2xy\times36}\longrightarrow$ Use prime factorization.
$\frac{(3\times3)(2\times2\times2)xy}{2xy(2\times2\times3\times3)}\longrightarrow$ Reorder smallest to largest.
$\frac{2\times2\times2\times3\times3\times xy}{2\times2\times2\times3\times3\times xy}\longrightarrow$ Identify factors that cancel (indicated with a line over the top).
$\frac{\overline{2\times2\times2\times3\times3\times xy}}{\overline{2\times2\times2\times3\times3\times xy}}\longrightarrow$ All factors cancel, leaving 1 in the numerator and denominator.
$\frac{1}{1}$ = $1$
