Answer
The two equations are not equal to each other because 0 is the only viable solution.
Work Step by Step
To see if $\frac{2+x}{8}$ and $\frac{1+x}{4}$ are equal, try to solve for an equation in which the two expressions are equal, as shown below.
$(2+x)\div8=(1+x)\div4$
$((2+x)\div8)\times8=((1+x)\div4)\times8$
$2+x=2+2x$
$(2+x)-2=(2+2x)-2$
$x=2x$
As shown below, unless $x=0$, the two expressions are not equal. For the two to be equal, they have to be the same no matter the variable.
