Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-5 - Cumulative Review - Page 372: 4

Answer

$$\frac{1}{9x^4y^6}$$

Work Step by Step

We know the following rules of exponents. $$ (1) \ a^m\cdot a^n = a^{m+n} \\ (2) \ (ab)^m =a^mb^m \\ (3) \ (a^m)^n =a^{mn} \\ (4) \ a^{-m} = \frac{1}{a^m} \\ (5)\ \frac{a^m}{a^n} =a^{m-n} \\ (6) \ a^0=1 \\ (7) \ (\frac{a}{b})^m =\frac{a^m}{b^m}$$ Thus, we find: $$ \left(3x^2y^3\right)^{-2}\\ \frac{1}{\left(3x^2y^3\right)^2}\\ \frac{1}{3^2x^4y^6} \\ \frac{1}{9x^4y^6}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.