Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-5 - Cumulative Review - Page 372: 12

Answer

$$-4t^{11}+8t^9+20t^8$$

Work Step by Step

We multiply these expressions out using the distributive property, ensuring that every value multiplied by a given set of parenthesis is multiplied by everything inside of the parenthesis. Doing this, we find: $$ \left(-4t^8\right)t^3+\left(-4t^8\right)\left(-2t\right)+\left(-4t^8\right)\left(-5\right)\\ -4t^8t^3+4\cdot \:2t^8t+4\cdot \:5t^8\\ -4t^{11}+8t^9+20t^8$$
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