Answer
$$\frac{4x^3-10x^2+x-2}{2}$$
Work Step by Step
We simplify the expression by finding common factors in the numerator and the denominator. Doing this, we find:
$$\frac{8x^4-20x^3+2x^2-4x}{4x}\\ \frac{2x\left(4x^3-10x^2+x-2\right)}{4x}\\ \frac{4x^3-10x^2+x-2}{2}$$
