## Elementary Algebra

$3x^2y\sqrt[]{7}$
Using the properties of radicals, the given expression, $\sqrt[]{63x^4y^2} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[]{9x^4y^2\cdot7} \\\\= \sqrt[]{(3x^2y)^2\cdot7} \\\\= 3x^2y\sqrt[]{7} .\end{array} Note that all of the variables are assumed to represent non-negative real numbers.