Elementary Algebra

$4x\sqrt[3]{xy^2}$
Using the properties of radicals, the given expression, $\sqrt[3]{64x^4y^2} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{64x^3\cdot xy^2} \\\\= \sqrt[3]{(4x)^3\cdot xy^2} \\\\= 4x\sqrt[3]{xy^2} .\end{array}Note that all of the variables are assumed to represent non-negative real numbers.