Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.2 - Simplifying Radicals - Problem Set 9.2: 36

Answer

$2x\sqrt{{6x}}$

Work Step by Step

RECALL: For any non-negative real number, $\sqrt{a^2} = a$ Factor the radicand (which is the expression inside the radical sign) so that at least one factor is a square, and then simplify using the rule above to obtain: $=\sqrt{4x^2(6x)} \\=\sqrt{(2x)^2(6x)} \\=2x\sqrt{{6x}}$
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