# Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.3 - Factoring Trinomials of the Form x^2+bx+x - Problem Set 6.3: 39

The solution set is $\left\{-4, 10\right\}$.

#### Work Step by Step

Factor the trinomial by looking for the factors of $-40$ whose sum is equal to the coefficient of the middle term ($-6$). These factors are $-10$ and $4$. This means that the factored form of the trinomial is $(n-10)(n+4)$. Thus, $n^2-6n-40=0 \\(n-10)(n+4)=0$ Equate each factor to 0; then, solve each equation to obtain: $n-10=0 \text{ or } n+4=0 \\n=10 \text{ or } n=-4$ The solution set is $\left\{-4, 10\right\}$.

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