Answer
$(n-2)(n-5)$
Work Step by Step
The following pairs of numbers give a product of $
10
:$
\begin{array}{l}\require{cancel}
\{ 1,10 \}
\text{ }
\{ -1,-10 \}
\text{ }
\{ 2,5 \}
\text{ }
\{ -2,-5 \}
.\end{array}
Of these pairs, the one which gives a sum of $
-7
$ is the pair $\{
-2,-5
\}.$
Hence, the factored form of the given expression, $
n^2-7n+10
$ is
\begin{array}{l}\require{cancel}
(n-2)(n-5)
.\end{array}
