# Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.3 - Factoring Trinomials of the Form x^2+bx+x - Problem Set 6.3 - Page 255: 10

$(n-3)(n+6)$

#### Work Step by Step

The following pairs of numbers give a product of $-18 :$ \begin{array}{l}\require{cancel} \{ 1,-18 \} \text{ } \{ -1,18 \} \text{ } \{ 2,-9 \} \text{ } \{ -2,9 \} \text{ } \{ 3,-6 \} \text{ } \{ -3,6 \} .\end{array} Of these pairs, the one which gives a sum of $3$ is the pair $\{ -3,6 \}.$ Hence, the factored form of the given expression, $n^2+3n-18$ is \begin{array}{l}\require{cancel} (n-3)(n+6) .\end{array}

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