#### Answer

$(2x-y)(4x^2+2xy+y^2)$

#### Work Step by Step

Using $a^3-b^3=(a-b)(a^2+ab+b^2)$ or the factoring of the difference of $2$ cubes, the factored form of the given expression, $
8x^3-y^3
,$ is \begin{array}{l}\require{cancel}
(2x-y)[(2x)^2+2x(y)+(y)^2]
\\\\=
(2x-y)(4x^2+2xy+y^2)
.\end{array}