## Elementary Algebra

$(x+1)(x^2-x+1)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of $2$ cubes, the factored form of the given expression, $x^3+1 ,$ is \begin{array}{l}\require{cancel} (x+1)[(x)^2-x(1)+(1)^2] \\\\= (x+1)(x^2-x+1) .\end{array}