Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.2 - Factoring the Difference of Two Squares - Problem Set 6.2: 49

Answer

The solution set is $\left\{-4, 4\right\}$.

Work Step by Step

Add $-16$ to both sides to obtain: $x^2-16=0 \\x^2-4^2=0$ RECALL: A difference of two squares can be factored using the formula: $a^2-b^2=(a-b)(a+b)$ Factor the difference of two squares to obtain: $(x-4)(x+4)=0$ Equate each factor to 0, and then solve each equation to obtain: $x-4=0 \text{ or } x+4 = 0 \\x=4 \text{ or } x=-4$ The solution set is $\left\{-4, 4\right\}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.