Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.2 - Factoring the Difference of Two Squares - Problem Set 6.2: 45

Answer

The solution set is $\left\{-3, 3\right\}$.

Work Step by Step

Add $-9$ to both sides to obtain: $x^2-9=0$ RECALL: A difference of two square can be factored using the formula: $x^2-y^2=(x-y)(x+y)$ Factor the difference of two squares to obtain: $(x-3)(x-3)=0$ Equate each factor to 0, and then solve each equation to obtain: $x-3=0 \text{ or } x+3 = 0 \\x=3 \text{ or } x =-3$ The solution set is $\left\{-3, 3\right\}$.
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