Answer
$8n^3+36n^2+54n+27$
Work Step by Step
We multiply each of the factors by each other to find:
$(2n+3)^3=(2n+3)(2n+3)(2n+3) = (4n^2+12n+9)(2n+3)=8n^3+12n^2+24n^2+36n+18n+27=
8n^3+36n^2+54n+27$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 5 - Exponents and Polynomials - Chapters 1-5 Cumulative Review Problem Set - Page 233: 27
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