Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapters 1-5 Cumulative Review Problem Set: 27

Answer

$8n^3+36n^2+54n+27$

Work Step by Step

We multiply each of the factors by each other to find: $(2n+3)^3=(2n+3)(2n+3)(2n+3) = (4n^2+12n+9)(2n+3)=8n^3+12n^2+24n^2+36n+18n+27= 8n^3+36n^2+54n+27$
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