## Elementary Algebra

$8n^3+36n^2+54n+27$
We multiply each of the factors by each other to find: $(2n+3)^3=(2n+3)(2n+3)(2n+3) = (4n^2+12n+9)(2n+3)=8n^3+12n^2+24n^2+36n+18n+27= 8n^3+36n^2+54n+27$