# Chapter 5 - Exponents and Polynomials - Chapters 1-5 Cumulative Review Problem Set - Page 233: 10

$\frac{7}{4}$

#### Work Step by Step

$2^{0}$ + $2^{-1}$ + $2^{-2}$ = Recall: $a^{-b}$ = $\frac{1^{b}}{a^{b}}$ So, we have: $2^{0}$ + $\frac{1^{1}}{2^{1}}$ + $\frac{1^{2}}{2^{2}}$ = 1 + $\frac{1}{2}$ + $\frac{1}{4}$ = Make all of the denominators equal. $\frac{4}{4}$ $\times$ 1 + $\frac{2}{2}$ $\times$ $\frac{1}{2}$ + $\frac{1}{4}$ = $\frac{4}{4}$ + $\frac{2}{4}$ + $\frac{1}{4}$ = $\frac{7}{4}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.