# Chapter 5 - Exponents and Polynomials - Chapters 1-5 Cumulative Review Problem Set - Page 233: 20

$-6x^{2}y+15xy^{2}$

#### Work Step by Step

We will solve this expression by removing the parenthesis. The only way the parenthesis can be removed is through multiplication of the common factor with each term inside the parenthesis. Therefore, we multiply the $-3xy$ with each term inside the parenthesis, using the rule $x^{a}\times x^{b}=x^{a+b}$ to multiply similar variables together: $-3xy(2x-5y)$ =$-3xy(2x)-3xy(-5y)$ =$(-3\times2\times x\times x \times y)-(3\times-5\times x \times y \times y)$ =$(-6x^{1+1}y)-(-15xy^{1+1})$ =$(-6x^{2}y)-(-15xy^{2})$ =$-6x^{2}y+15xy^{2}$

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