Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Test: 7

Answer

$n^{2}+7n-98$

Work Step by Step

To find the product of $(n+14)$ and $(n-7)$, we need to use the distributive property in which each term of the first polynomial is multiplied to each term of the second polynomial: $(n+14)(n-7)$ =$n(n-7)+14(n-7)$ =$n^{2}-7n+14n-98$ =$n^{2}+7n-98$
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