Answer
$\frac{27}{8}$
Work Step by Step
Recall the following rule: $(\frac{a}{b})^{-x}=\frac{b^{x}}{a^{x}}$. Thus, we obtain:
$(\frac{2}{3})^{-3}=\frac{2^{-3}}{3^{-3}}=\frac{3^{3}}{2^{3}}=\frac{27}{8}$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 5 - Exponents and Polynomials - Chapter 5 Test - Page 232: 17
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