Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Test: 17

Answer

$\frac{27}{8}$

Work Step by Step

Recall the following rule: $(\frac{a}{b})^{-x}=\frac{b^{x}}{a^{x}}$. Thus, we obtain: $(\frac{2}{3})^{-3}=\frac{2^{-3}}{3^{-3}}=\frac{3^{3}}{2^{3}}=\frac{27}{8}$
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