Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Test - Page 232: 2



Work Step by Step

Since $(-x^{2}+9x-14)$ is subtracted from $(-4x^{2}+3x+6)$, we write the following expression: $(-4x^{2}+3x+6)-(-x^{2}+9x-14)$ Now, we multiply the second polynomial with $-1$ in order to remove the parenthesis: $(-4x^{2}+3x+6)-(-x^{2}+9x-14)$ =$-4x^{2}+3x+6+x^{2}-9x+14$ Next, we collect like terms together and then add/subtract them together: $-4x^{2}+3x+6+x^{2}-9x+14$ =$(-4x^{2}+x^{2})+(3x-9x)+(6+14)$ =$(-3x^{2})+(-6x)+(20)$ =$-3x^{2}-6x+20$
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