## Elementary Algebra

$-3x^{2}-6x+20$
Since $(-x^{2}+9x-14)$ is subtracted from $(-4x^{2}+3x+6)$, we write the following expression: $(-4x^{2}+3x+6)-(-x^{2}+9x-14)$ Now, we multiply the second polynomial with $-1$ in order to remove the parenthesis: $(-4x^{2}+3x+6)-(-x^{2}+9x-14)$ =$-4x^{2}+3x+6+x^{2}-9x+14$ Next, we collect like terms together and then add/subtract them together: $-4x^{2}+3x+6+x^{2}-9x+14$ =$(-4x^{2}+x^{2})+(3x-9x)+(6+14)$ =$(-3x^{2})+(-6x)+(20)$ =$-3x^{2}-6x+20$