#### Answer

False

#### Work Step by Step

$\frac{x^{3}}{x^{3}}$ = 0
To check if this is true or not, we simplify the left side.
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{x^{3}}{x^{3}}$ = $x^{3-3}$ = $x^{0}$ = 1
Because 1 is not equal to 0, this statement is false.