Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.4 - Dividing by Monomials - Concept Quiz 5.4 - Page 211: 4

Answer

False

Work Step by Step

$\frac{6x^{5} + 3x}{3x}$ = 2$x^{4}$ To check if this is true or not, we simplify the left side. RECALL: $\frac{b^{n}}{b^{m}}$ = $b^{n-m}$ So, $\frac{6x^{5} + 3x}{3x}$ = $\frac{6x^{5}}{3x}$ + $\frac{3x}{3x}$ = $\frac{6}{3}$$x^{5-1}$ + $\frac{3}{3}$$x^{1-1}$ = 2$x^{4}$ + 1 Because 2$x^{4}$ + 1 is not equal to 2$x^{4}$, this statement is false.
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