## Elementary Algebra

$\frac{6x^{5} + 3x}{3x}$ = 2$x^{4}$ To check if this is true or not, we simplify the left side. RECALL: $\frac{b^{n}}{b^{m}}$ = $b^{n-m}$ So, $\frac{6x^{5} + 3x}{3x}$ = $\frac{6x^{5}}{3x}$ + $\frac{3x}{3x}$ = $\frac{6}{3}$$x^{5-1} + \frac{3}{3}$$x^{1-1}$ = 2$x^{4}$ + 1 Because 2$x^{4}$ + 1 is not equal to 2$x^{4}$, this statement is false.