## Elementary Algebra

$\frac{y^{8}}{y^{4}}$ = $y^{2}$ To check if this is true or not, we simplify the left side. RECALL: $\frac{b^{n}}{b^{m}}$ = $b^{n-m}$ So, $\frac{y^{8}}{y^{4}}$ = $y^{8-4}$ = $y^{4}$ Because $y^{4}$ is not equal to $y^{2}$, this statement is false.