#### Answer

False.

#### Work Step by Step

$\frac{y^{8}}{y^{4}}$ = $y^{2}$
To check if this is true or not, we simplify the left side.
RECALL:
$\frac{b^{n}}{b^{m}}$ = $b^{n-m}$
So, $\frac{y^{8}}{y^{4}}$ =
$y^{8-4}$ =
$y^{4}$
Because $y^{4}$ is not equal to $y^{2}$, this statement is false.