Answer
64$n^{3}$ - 144$n^{2}$ + 108n - 27
Work Step by Step
$(4n - 3)^{3}$ =
(4n - 3)(4n - 3)(4n - 3) =
Remember that $(a-b)^{2}$ = $a^{2}$ - 2ab + $b^{2}$.
So, (4n - 3)(4n - 3)(4n - 3) =
[$(4n)^{2}$ - 2$\times$4n$\times$3 + $3^{2}$](4n - 3) =
(16$n^{2}$ - 24n + 9)(4n - 3) =
Use the distributive property.
16$n^{2}$(4n) +16$n^{2}$(-3) -24n(4n) -24n(-3) +9(4n) +9(-3) =
64$n^{3}$ - 48$n^{2}$ - 96$n^{2}$ + 72n + 36n - 27
Simplify.
64$n^{3}$ - 144$n^{2}$ + 108n - 27
