Answer
27$n^{3}$ - 54$n^{2}$ + 36n - 8
Work Step by Step
$(3n - 2)^{3}$ =
(3n - 2)(3n - 2)(3n - 2) =
Remember that $(a-b)^{2}$ = $a^{2}$ - 2ab + $b^{2}$.
So, (3n - 2)(3n - 2)(3n - 2) =
[$(3n)^{2}$ - 2$\times$3n$\times$2 + $2^{2}$](3n - 2) =
(9$n^{2}$ - 12n + 4)(3n - 2) =
Use the distributive property.
9$n^{2}$(3n) +9$n^{2}$(-2) -12n(3n) -12n(-2) +4(3n) +4(-2) =
27$n^{3}$ - 18$n^{2}$ - 36$n^{2}$ + 24n + 12n - 8 =
27$n^{3}$ - 54$n^{2}$ + 36n - 8