## Elementary Algebra

Published by Cengage Learning

# Chapter 4 - Proportions, Percents, and Solving Inequalities - Chapter 4 Review Problem Set - Page 183: 15

#### Answer

The car will use 30 gallons of gas on a 615-mile trip.

#### Work Step by Step

Let x represent the amount of gas the car will use on a 615-mile trip. Now, let’s set up a proportion in which one ratio compares the amount of fuel used and the other ratio compares the corresponding distances traveled. $\frac{18}{x}$ = $\frac{369}{615}$ To solve this equation, we equate the cross products. 18 $\times$ 615 = x $\times$ 369 11070 = 369x Divide both sides by 369. 30 = x The car will use 30 gallons of gas on a 615-mile trip.

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